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Question

Evaluate ∣ ∣xyx+yyx+yxx+yxy∣ ∣

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Solution

Let A=∣ ∣xyx+yyx+yxx+yxy∣ ∣

=∣ ∣ ∣2(x+y)yx+y2(x+y)x+yx2(x+y)xy∣ ∣ ∣
(using C1C1+C2+C3)
=2(x+y)∣ ∣1yx+y1x+yx1xy∣ ∣ |Taking out 2(x+y) common from C1|
=2(x+y)∣ ∣1yx+y0xy0xyx∣ ∣
(using R2R2R1;R3R3R1)
Expanding along R1, we get
=2(x+y)×1(x2+y(xy))=2(x+y)(x2+xyy2)=2(x+y)(x2xy+y2)=2(x3+y3)


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