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Question

Evaluate C20C21+C22......+(1)nC2n for n = 10 and n = 11

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Solution

For n = 10 the value ,
=(1)10/210C5=(1)5(10)!5!5!
=(1)510×9×8×7×654321=252
And for n = 11 , the value = 0 as 11/2 is not an integer

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