Question

Evaluate

$\frac{2\sin {68}^o}{\cos {22}^o}-\frac{2\cot {15}^o}{5\tan {75}^o}$

Answer 1

We have,

$\frac{2{\sin 68}^0}{{\cos 22}^0}-\frac{2\cot {15}^0}{{\tan 75}^0}$

$\Rightarrow \frac{2\sin ({90}^0-{22}^0)}{\cos {22}^0}-\frac{2\cot ({90}^0-{75}^0)}{\tan {75}^0}$

$\Rightarrow \frac{2\cos {22}^0}{{\cos 22}^0}-\frac{2\tan {75}^0}{{\tan 75}^0}$

$=2-2$

$\Rightarrow 0$

Hence, this is the answer.