Question

Evaluate : $\frac{{\sin }^2{63}^o+{\sin }^2{27}^o}{{\cos }^2{17}^o+{\cos }^2{73}^o}$

Answer 1

$\frac{{\sin }^{2}63+{\sin }^{2}27}{{\cos }^{2}17+{\cos }^2{73}^o}$

$=\frac{{\sin }^2(90-27)+{\sin }^{2}27}{{\cos }^2(90-73)+{\cos }^2{73}^o}$

$=\frac{{\cos }^2{27}^o+{\sin }^2{27}^o}{{\cos }^2{73}^o+{\sin }^2{73}^o}=\frac{1}{1}=1$.