evaluate cos 48 degree. cos 42 degrees - sin 48 degree.sin 42 degree

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Solution

$\cos 48 ° . \cos 42 ° - \sin 48 ° . \sin 42 ° = \cos (90 ° - 42 °) . \cos (90 ° - 48 °) - \sin 48 ° . \sin 42 ° = \sin 42 ° . \sin 48 ° - \sin 48 ° . \sin 42 ° [as, \cos (90 ° - θ) = \sin θ] = 0$

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c o s 48^{\circ} - s i n 42^{\circ} =

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