Evaluate:cos60°×cos30°+sin60°×sin30°
Given that cos60°×cos30°+sin60°×sin30°
Formula used [Cos(A-B)=CosACosB+SinASinB]
cos60°×cos30°+sin60°×sin30°=cos(600-300)
=cos300
=32 (cos300=√32)
Thus, cos60°×cos30°+sin60°×sin30°=32