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Trigonometric Ratios of Complementary Angles

Evaluate 34...

Question

Evaluate $cot 34^{o} - tan 56^{o}$

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Solution

Consider $cot 34^{0}$ which can be rewritten as follows:

$cot 34^{0} = cot {(90^{0} - 56}^{0}) = tan 56^{0} (∵ cot (90^{0} - x) = tan x)$

Therefore, $cot 34^{0} - tan 56^{0}$ can be evaluated as shown below:

$cot 34^{0} - tan 56^{0} = tan 56^{0} - tan 56^{0} = 0$

Hence, $cot 34^{0} - tan 56^{0} = 0$ .

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Q. The value of

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Q. Two supplementary angles differ by

34^{o}

. Then the angles are __________.

Q. In the given alongside :
If

∠ B O C = ∠ D O C = 34^{o}

∠ A O D = 120^{o}

A O B

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