CameraIcon

SearchIcon

MyQuestionIcon

210

You visited us 210 times! Enjoying our articles? Unlock Full Access!

Trigonometric Ratios of Compound Angles

Evaluate: 6...

Question

Evaluate:
$csc (65^{o} + 0) - sec (25^{o} - 0) - t a n (55^{o} + 0) + cot (35^{o} - 0)$ ?

Open in App

Solution

$C o s e c (65 + θ) - sec (25 - θ) - tan (55 - θ) + cot (35 + θ)$

$= sec [90 - (65 + θ)] - sec (25 - θ) - cot [90 - (55 - θ)] + cot (35 + θ)$
$s i n c e sec (90 - x) = c o s e c x, cot (90 - x) = t a n x$

$= sec (25 - θ) - sec (25 - θ) - cot (35 + θ) + cot (35 + θ)$

$= 0$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The value of

{sin}^{2} 65^{o} + {sin}^{2} 25^{o} + {cos}^{2} 35^{o} + {cos}^{2} 55^{o}

tan (55^{o} - A) - cot (35^{o} + A)

\frac{{sec}^{2} (90^{o} - θ) - {cot}^{2} θ}{2 ({sin}^{2} 25^{o} + {sin}^{2} 65^{o})} + \frac{2 {cos}^{2} 60^{o} {tan}^{2} 28^{o} {tan}^{2} 62^{o}}{sin 30^{o} cos 60^{o}}

\frac{c o s e c^{2} 63^{o} + {tan}^{2} 24^{o}}{{cot}^{2} 66^{o} + {sec}^{2} 27^{o}} + \frac{{sin}^{2} 63^{o} + {cos}^{2} 63^{o} sin 27^{o} + sin 27^{o} sec 63^{o}}{2 (c o {sec}^{2} 65^{o} - {tan}^{2} 25^{o})}

{sec}^{2} 60^{0} + sec 0^{0}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Compound Angles

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Trigonometric Ratios of Compound Angles

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon