Question

Evaluate definite integral as limit of sums : ${\int }_{-1}^1{e}^{x}dx$

Answer 1

We have,

$I={\int }_{-1}^1{e}^{x}dx=e^x$

$I={\int }_{-1}^1{e}^{x}dx=e-\frac{1}{e}$

Hence, this is the answer.