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Byju's Answer
Standard XII
Mathematics
Determinant
Evaluate : Δ...
Question
Evaluate :
Δ
=
∣
∣ ∣
∣
cos
α
cos
β
cos
α
sin
β
−
sin
α
−
sin
β
cos
β
0
sin
α
cos
β
sin
α
sin
β
cos
α
∣
∣ ∣
∣
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Solution
∣
∣ ∣
∣
cos
α
cos
β
cos
α
sin
β
−
sin
α
−
sin
β
cos
β
0
sin
α
cos
β
sin
α
sin
β
cos
α
∣
∣ ∣
∣
[
R
′
1
=
R
1
−
(
cot
α
)
R
3
]
=
∣
∣ ∣
∣
0
0
−
cosec
α
−
sin
β
cos
β
0
sin
α
cos
β
sin
α
sin
β
cos
α
∣
∣ ∣
∣
=
(
−
cosec
α
)
.
(
−
sin
α
)
.
(
sin
2
β
+
cos
2
β
)
[Expanding with respect to first row]
=
1
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Similar questions
Q.
Evaluate
∣
∣ ∣
∣
cos
α
cos
β
cos
α
sin
β
−
sin
α
−
sin
β
cos
β
0
sin
α
cos
β
sin
α
sin
β
cos
α
∣
∣ ∣
∣
Q.
The value of the determinant
Δ
=
∣
∣ ∣
∣
cos
α
cos
β
cos
α
sin
β
−
sin
α
−
sin
β
cos
β
0
sin
α
cos
β
sin
α
sin
β
cos
α
∣
∣ ∣
∣
is
Q.
If
x
=
sin
(
α
−
β
)
.
sin
(
γ
−
δ
)
;
y
=
sin
(
β
−
γ
)
.
sin
(
α
−
δ
)
and
z
=
sin
(
γ
−
α
)
.
sin
(
β
−
δ
,
)
then
Q.
Without expanding evaluate the determinant;
∣
∣ ∣ ∣
∣
s
i
n
α
c
o
s
α
s
i
n
(
α
+
δ
)
s
i
n
β
c
o
s
β
s
i
n
(
β
+
δ
)
s
i
n
γ
c
o
s
γ
s
i
n
(
γ
+
δ
)
∣
∣ ∣ ∣
∣
Q.
If
α
,
β
,
γ
,
δ
are in arithmetic progression.
Then
sin
(
α
+
β
+
γ
+
δ
)
is equal to
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