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Question

Evaluate :
Δ=∣ ∣cosαcosβcosαsinβsinαsinβcosβ0sinαcosβsinαsinβcosα∣ ∣

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Solution

∣ ∣cosαcosβcosαsinβsinαsinβcosβ0sinαcosβsinαsinβcosα∣ ∣

[R1=R1(cotα)R3]

=∣ ∣00cosecαsinβcosβ0sinαcosβsinαsinβcosα∣ ∣

=(cosecα).(sinα).(sin2β+cos2β)
[Expanding with respect to first row]

=1

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