The correct option is A 11
1112×1211312112×1113=1112×(112)13(112)12×1113
=1112×(11)2×13(11)2×12×1113 (Using properties of exponent, that is (am)n=am×n)
=1112×11261124×1113
=(11)12+26(11)24+13 (Using properties of exponent, that is am×an=am+n)
=11381137
=(11)38−37 (Using properties of exponent, that is am÷an=am−n)
=111=11