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Question

Evaluate: 1112×1211312112×1113

A
11
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B
1125
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C
110 or 1
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D
110+1210
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Solution

The correct option is A 11
1112×1211312112×1113=1112×(112)13(112)12×1113

=1112×(11)2×13(11)2×12×1113 (Using properties of exponent, that is (am)n=am×n)

=1112×11261124×1113

=(11)12+26(11)24+13 (Using properties of exponent, that is am×an=am+n)

=11381137
=(11)3837 (Using properties of exponent, that is am÷an=amn)
=111=11

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