wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate : cos58sin32+sin22cos68cos38csc52tan18tan35tan60tan72tan55

Open in App
Solution

We know that,

cos(90θ)=sinθ

sin(90θ)=cosθ

tan(90θ)=cotθ


cscθ=1sinθ


cos58sin32+sin22cos68cos38csc52tan18tan35tan60tan72tan55

=cos(9032)sin32+sin(9068)cos68cos(9052)sin52tan(9072)tan(9055)tan60tan72tan55

=sin32sin32+cos68cos68sin52sin52cot72cot55tan60tan72tan55

=1+1sin52tan72tan55sin52tan60tan72tan55

=1+11tan60

=213

=2313

Multiply numerator and denominator by 3

=633

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Trigonometric Ratios of Complementary Angles
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon