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Complementary Trigonometric Ratios

Evaluate : ...

Question

Evaluate $: \frac{cot 63 ˚}{tan 27 ˚}$

A

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B

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C

2

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D

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Solution

The correct option is D $1$
We know that
$tan A = cot (90 ˚ - A)$

$\frac{cot 63 ˚}{tan 27 ˚} = \frac{tan (90 ˚ - 63 ˚)}{tan 27 ˚} = \frac{tan 27 ˚}{tan 27 ˚} = 1$

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\frac{cot 63^{\circ}}{tan 27^{\circ}}

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