CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Complementary Trigonometric Ratios

Evaluate : ...

Question

Evaluate $: \frac{cot 63 ˚}{tan 27 ˚}$

A

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

- 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $1$
We know that
$tan A = cot (90 ˚ - A)$

$\frac{cot 63 ˚}{tan 27 ˚} = \frac{tan (90 ˚ - 63 ˚)}{tan 27 ˚} = \frac{tan 27 ˚}{tan 27 ˚} = 1$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Without trigonometric table, evaluate

\frac{cot 63^{\circ}}{tan 27^{\circ}}

\frac{{c o s e c}^{2} 63^{0} + {t a n}^{2} 24^{0}}{{c o t}^{2} 66^{0} + {s e c}^{2} 27^{0}} + \frac{{s i n}^{2} 63^{0} + c o s 63^{0} {s i n 27}^{0} + {s i n 27}^{0} {s e c 63}^{0}}{2 ({c o s e c}^{2} 65^{0} - {t a n}^{2} 25^{0})}

\frac{{sin}^{2} 63^{0} + {sin}^{2} 27^{o}}{{cos}^{2} 17^{o} + {cos}^{2} 73^{o}}

Q. State true or false

tan 18^{0} + tan 27^{0} + tan 18^{0} \cdot tan 27^{0} = 1

6 \frac{3}{4} + 2 \frac{1}{2}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Trigonometric Ratios of Complementary Angles

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Complementary Trigonometric Ratios

Standard X Mathematics

Join BYJU'S Learning Program

CrossIcon