1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Principal Solution of Trigonometric Equation
Evaluate: 1...
Question
Evaluate:
csc
13
o
sec
77
o
−
cot
20
o
tan
70
o
.
Open in App
Solution
csc
13
∘
sec
77
∘
−
cot
20
∘
tan
70
∘
=
csc
(
90
−
77
)
∘
sec
77
∘
−
cot
(
90
−
70
)
∘
tan
70
∘
=
sec
77
∘
sec
77
∘
−
tan
70
∘
tan
70
∘
=
1
−
1
=
0
Suggest Corrections
0
Similar questions
Q.
Evaluate
cos
2
13
o
−
sin
2
77
o
Q.
Prove that
(
1
+
sec
20
o
+
cot
70
o
)
(
1
−
c
o
s
e
c
20
o
+
tan
70
o
)
=
2
.
Q.
Evaluate:
s
i
n
2
70
o
c
o
s
2
20
o
+
c
s
c
2
20
o
s
e
c
2
70
o
−
2
c
o
s
70
o
c
o
s
e
c
20
o
Q.
Evaluate:
cos
2
20
o
+
cos
2
70
o
sec
2
50
o
−
cot
2
40
o
+
2
cosec
2
58
o
−
2
cot
58
o
tan
32
o
−
4
tan
13
o
tan
37
o
tan
45
o
tan
53
o
tan
77
o
Q.
Prove:
tan
70
o
−
tan
20
o
=
2
tan
50
o
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Principal Solution
MATHEMATICS
Watch in App
Explore more
Principal Solution of Trigonometric Equation
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app