Question

Evaluate:
$\frac{{\sin }^2{63}^0+{\sin }^2{27}^0}{{\cos }^2{17}^0+{\cos }^2{73}^0}$

• A. $1$
• B. $-1$
• C. $0$
• D. Both $A$ and $B$

Answer 1

The correct option is A $1$

$=\frac{{\sin }^{2}63°+{\sin }^{2}27°}{{\cos }^{2}17°+{\cos }^{2}73°}$

$=\frac{{\sin }^{2}63°+{\sin }^2(90-63)}{{\cos }^2(90-73)+{\cos }^{2}73°}$

$=\frac{{\sin }^{2}63°+{\cos }^{2}63°}{{\sin }^{2}73°+{\cos }^{2}73°}$

$⟹\frac{1}{1}=1$