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Question

Evaluate: sin4θcos4θsin2θcos2θ

A
3
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B
2
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C
0
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D
1
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Solution

The correct option is A 1
sin4θcos4θsin2θcos2θ

=(sin2θcos2θ)(sin2θ+cos2θ)sin2θcos2θ

=sin2θ+cos2θ=1

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