Evaluate - sinAcosA-1

sinAcosA+1 =sinAcosA+1×cosA 1cosA 1 = sinA(1 cosA) (1 cos^2A) =sinA(1 cosA)sin^2A =(1 cosA)sinA =1sinA cosAsinA =A A ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Domain and Range of Basic Inverse Trigonometric Functions

Evaluate : s...

Question

Evaluate : $\frac{sin A}{cos A + 1}$

Open in App

Solution

Suggest Corrections

Similar questions

\frac{1 + sin A}{sin A} - \frac{{sin}^{2} A}{1 + cos A}

cos A = \frac{5}{13}

\frac{sin A - cot A}{2 tan A}

cot A + \frac{1}{cos A}

5 c o s A - 12 s i n A = 0

\frac{s i n A + c o s A}{2 c o s A - s i n A}

\frac{1 + cos A - sin A}{1 + cos A + sin A} = sec A - tan A = \frac{1 - sin A}{cos A} = \sqrt{\frac{1 - sin A}{1 + sin A}}

\frac{1 + cos A + sin A}{1 + cos A - sin A} = \frac{1 + sin A}{cos A}

Join BYJU'S Learning Program