Question

Evaluate:

$\frac{\tan {26}^o}{\cot {64}^o}$ ?

Answer 1

$\frac{\tan {26}^o}{\cot {64}^o}=\frac{\tan ({90}^o-{64}^o)}{\cot {64}^o}=\frac{\cot {64}^o}{\cot {64}^o}=1$
(Using the fact that: $\tan ({90}^o-x)=\cot \left(x\right)$)