Question

Evaluate: $\frac{\tan {30}^{\circ }}{\cot {60}^{\circ }}$

• A. $\frac{1}{\sqrt{2}}$
• B. $\frac{1}{\sqrt{3}}$
• C. $\sqrt{3}$
• D. $1$

Answer 1

Answer: (D)

$1$

Taking$\frac{\tan {30}^{\circ }}{\cot {60}^{\circ }}$

$\frac{\tan {30}^{\circ }}{\cot (90-30{)}^{\circ }}$

as we know, $\cot ({90}^0-\theta )=\tan \theta$

$\frac{\tan {30}^{\circ }}{\tan {30}^{\circ }}$

$=1$