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Question

Evaluate :
tan76cot14+sec58cosec32sin35sec55+8sin230

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Solution

(tan76ocot14o)+(sec58ocosec32o)sin35osec55o+8sin230o

usetan(90oθ)=cotθ

sec(90oθ)=cosecθ

sin(90oθ)=cosθ

(tan(90o14o)cot14o)+(sec(90o32o)cosec32o)sin35osec(90o35o)+8sin230o

=(cot14ocot14o)+(cosec32ocosec32o)sin35ocosec35o+8(12)2

=21+2

=3


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