Evaluate- 3 2 60 o - 4 45 o -tan 2 60 o

The correct option is A 0 Given that: 3 ^ 2 60^o #160; + ^ 4 #160; 45 ^o #160; tan ^ 2 60^∘ #160; #160; =3 ^ 2 ( #160; 90 ^o ...

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Circular Measurement of Angle

Evaluate: 3...

Question

Evaluate: $3 {cot}^{2} 60^{o} + {sec}^{4} 45^{o} - {tan}^{2} 60^{o}$

0

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\frac{{tan}^{2} 60^{o} + 4 {cos}^{2} 45^{o} + 3 {sec}^{2} 30^{o} + 5 {cos}^{2} 90^{o}}{c o sec 30^{o} + sec 60^{o} - {cot}^{2} 30^{o}}

\frac{{tan}^{2} 60^{o} + 4 {sin}^{2} 45^{o} + {sin}^{2} 90^{o}}{3 {sec}^{2} 30^{o} + {csc}^{2} 60^{o} - {cot}^{2} 30^{o}}

\frac{1 + {tan}^{2} 30^{o}}{1 - {tan}^{2} 30^{o}} + {csc}^{2} 60^{0} - {cos}^{2} 45^{o} + {sin}^{2} 45^{o} + \frac{1 + {cot}^{2} 60^{o}}{1 - {cot}^{2} 60^{o}}

\frac{x {cosec}^{2} 30^{o} {sec}^{2} 45^{o}}{8 {cos}^{2} 45^{o} {sin}^{2} 90^{o}} = {tan}^{2} 60^{o} - {tan}^{2} 45^{o}

x

\frac{2}{3} ({cos}^{4} 30^{o} - {sin}^{4} 45^{o}) - 3 ({sin}^{2} 60^{o} - {sec}^{2} 45^{o}) + \frac{1}{4} {cot}^{2} 30^{o}

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