Evaluate :
$(- 32)^{\frac{2}{5}}$

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Solution

We have $(- 32)^{\frac{2}{5}}$
$= (- 2^{5})^{\frac{2}{5}}$
$= (- 2)^{\frac{2 \times 5}{5}}$
$= (- 2)^{2}$
$= 4$

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