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Question

Evaluate: 0.06×0.06×0.060.05×0.05×0.050.06×0.06+0.06×0.05+0.05×0.05

A
0.01
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B
0.001
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C
0.1
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D
0.02
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Solution

The correct option is A 0.01
We know that one of the identity of polynomials is:
a3b3=(ab)(a2+ab+b2)

Now let us substitute a=0.06 and b=0.05 in the above identity as follows:
(0.06)3(0.05)3=(0.060.05){(0.06)2+(0.06×0.05)+(0.05)2}

0.06×0.06×0.060.05×0.05×0.05=0.01×(0.06×0.06+0.06×0.05+0.05×0.05) .....(1)

Now consider the given expression as shown below:
0.06×0.06×0.060.05×0.05×0.050.06×0.06+0.06×0.05+0.05×0.05

=0.01×(0.06×0.06+0.06×0.05+0.05×0.05)0.06×0.06+0.06×0.05+0.05×0.05 ...From eqn (1)
=0.01

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