wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate: 0.06×0.06×0.060.05×0.05×0.050.06×0.06+0.06×0.05+0.05×0.05

A
0.01
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.001
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.02
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.01
We know that one of the identity of polynomials is:
a3b3=(ab)(a2+ab+b2)

Now let us substitute a=0.06 and b=0.05 in the above identity as follows:
(0.06)3(0.05)3=(0.060.05){(0.06)2+(0.06×0.05)+(0.05)2}

0.06×0.06×0.060.05×0.05×0.05=0.01×(0.06×0.06+0.06×0.05+0.05×0.05) .....(1)

Now consider the given expression as shown below:
0.06×0.06×0.060.05×0.05×0.050.06×0.06+0.06×0.05+0.05×0.05

=0.01×(0.06×0.06+0.06×0.05+0.05×0.05)0.06×0.06+0.06×0.05+0.05×0.05 ...From eqn (1)
=0.01

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Polynomial and Its General Form
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon