Question

Evaluate $\frac{-12}{5}+\frac{31}{10}+\frac{11}{-15}+\frac{-7}{-18}$

Answer 1

$\frac{-12}{5}+\frac{31}{10}+\frac{11}{-15}+\left(\frac{-7}{-18}\right)$

$=\frac{-12\times 2}{5\times 2}+\frac{31}{10}-\frac{11}{15}+\frac{7}{18}$

$=\frac{31-24}{10}+\frac{7\times 5}{18\times 5}-\frac{11\times 6}{15\times 6}$

$=\frac{7}{10}+\frac{35-66}{90}$

$=\frac{7}{10}-\frac{31}{90}$

$=\frac{7\times 9}{10\times 9}-\frac{31}{90}=\frac{63}{90}-\frac{31}{90}$

$=\frac{32}{90}$

$=\frac{32}{90}=\frac{16}{25}$