Question

Evaluate: $\frac{2x^2-20x+50}{x-5}$

• A. $x+5$
• B. $2x-5$
• C. $2(x-5)$
• D. $x-5$

Answer 1

The correct option is C $2(x-5)$

$\frac{2x^2-20x+50}{x-5}=\frac{2(x^2-10x+25)}{x-5}$

$=\frac{2[{\left(x\right)}^2-2\left(x\right)\left(5\right)+{\left(5\right)}^2]}{(x-5)}$

$=\frac{2{(x-5)}^2}{x-5}$ $[\because (a+b{)}^2=a^2+2ab+b^2]$

$=2(x-5)$