CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Property 7

Evaluate: 3x...

Question

Evaluate: $\frac{3 x + 1}{6 x + 7} - \frac{x + 1}{2 x + 3} = 0$

Open in App

Solution

$\frac{3 x + 1}{6 x + 7} = \frac{x + 1}{2 x + 3} \Rightarrow 6 x^{2} + 11 x + 3 = 6 x^{2} + 13 x + 7 \Rightarrow - 2 x = 4 x = - 2$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Evaluate limit of the given function at x=0.

f (x) = \frac{6^{x} + 3^{x} - 2^{x} - 1}{x}

{lim}_{x - 1} \frac{x^{7} - 2 x^{5} + 1}{x^{3} - 3 x^{2} + 2}

\int \frac{1}{(2 x - 7)} \sqrt{(x - 3) (x - 4)} d x

lim x \to 1 \frac{x^{7} - 2 x^{5} + 1}{x^{3} - 3 x^{2} + 2}

Solve for x : \frac{6 x - 7}{2 x + 1} = \frac{3 x + 1}{x + 5}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Property 7

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon