Evaluate - 60pqr p 2 - q 2 q 2 - r 2 r 2 - p 2 - 30pq p 2 - q 2 r 2 - p 2

The correct option is C 2r( q ^ 2 + r ^ 2 ) 60pqr( p ^ 2 + q ^ 2 ) ( q ^ 2 + r ^ 2 ) ( r ^ 2 + p ^ 2 ) #160;/ 30pq( p ^ 2 + q ^ 2 ) ( r ^ 2 ...

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Sum of Binomial Coefficients of Odd Numbered Terms

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Question

Evaluate : $\frac{60 p q r (p^{2} + q^{2}) (q^{2} + r^{2}) (r^{2} + p^{2})}{30 p q (p^{2} + q^{2}) (r^{2} + p^{2})}$

\frac{1}{2} (q^{2} + r^{2})

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2 r (p^{2} + q^{2})

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2 r (q^{2} + r^{2})

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2 r (r^{2} + p^{2})

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Solution

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Similar questions

(p^{2} - 2 p q + q^{2}) - r^{2}

(p^{2} - q^{2}) x^{2} + (q^{2} - r^{2}) x + r^{2} - p^{2} = 0

(p^{2} - q^{2}) y^{2} + (r^{2} - p^{2}) y + q^{2} - r^{2} = 0

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- r^{2} + p^{2} + q^{2} - 2 p q

\frac{{(a^{p + q})}^{2} {(a^{q + r})}^{2} {(a^{r + p})}^{2}}{{(a^{p} . a^{q} . a^{r})}^{4}} = 1

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