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Question

Evaluate: tanθcot(90oθ)+secθcosec(90oθ)+sin235o+sin255otan10otan20otan30otan70otan80o.

A
3
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B
23
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C
32
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D
1
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Solution

The correct option is B 23
as we know cot(900 θ ) = tan θ and cosec(900 θ ) = sec θ
Numerator sec2 θ tan2 θ =1 and sin550= cos350
So using the above mentioned identity the numerator outcome is 2 and the denominator tan800= cot100 and tan100cot100=1 similarly for tan200cot200=1
so denominator is tan300=1/ 3
Hence answer is 2 3
Hence option B is correct.

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