Question

Evaluate: $\frac{x(8x^2-32)}{8x(x-4)}$

• A. $x+2$
• B. $x+4$
• C. $\frac{x^2-4}{x-4}$
• D. $x^2-4$

Answer 1

Answer: (C)

$\frac{x^2-4}{x-4}$

$\frac{x(8x^2-32)}{8x(x-4)}=\frac{8(x^2-4)}{8(x-4)}=\frac{(x^2-4)}{(x-4)}$