Evaluate $\int_{0}^{1} (1 - x^{2}) d x$

\frac{2}{3}

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\frac{3}{2}

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\frac{1}{2}

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\frac{1}{3}

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Solution

The correct option is A $\frac{2}{3}$

$\int_{0}^{1} 1 - x^{2} d x$

$= {[x - \frac{x^{3}}{3}]}_{0}^{1}$

$= 1 - \frac{1}{3}$

$= \frac{2}{3}$

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