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B
3
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C
4
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D
5
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Solution
The correct option is D 4 I=∫20∣∣x2+2x−3∣∣dx=∫10∣∣x2+2x−3∣∣dx+∫21∣∣x2+2x−3∣∣dx Therefore I=−∫10(x2+2x−3)dx+∫21(x2+2x−3)dx=−[x33+x2−3x]10+[x33+x2−3x]21=4