where, [x] denotes the greator integer less than or equal to 'x'
A
0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
∞
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A0 ∫∞∞[[x+1]e5x+2]dxletf(x)=[x+1]ex+2valueoff(0)=1e2∃(0,1)f(0)=2e3∃(0,1)f(0)=3e4∃(0,1)andsoonforallvalueofxf(x)∃(0,1)=[f(x)]=0[x]⟶G.1.F=∫∞0[f(x)]dx=∫∞00dx=0