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Question

Evaluate: π/20cosx(1+sinx)(2+sinx)dx

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Solution

Let sinx=t, then cosxdx=dt
Hence,
I=01dt(t+1)(t+2)

=01(t+2)(t+1)dt(t+1)(t+2)

=011t+11t+2dt

=[lnt+1t+2]01

=[ln0+10+2][ln1+11+2]

=ln(12)ln(23).

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