Evaluate:
$\int_{- 1}^{1} \frac{1}{x^{2}} d x$ .

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Solution

$\begin{matrix} = \int_{- 1}^{1} x^{- 2} d x {= [\frac{x^{- 1}}{- 1}]}_{- 1}^{1} = - {[\frac{1}{x}]}_{- 1}^{1} = - {[\frac{1}{1} - [\frac{1}{- 1}]]} = - 2 \end{matrix}$

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