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Question

Evaluate: 11|x+2|x+2dx

A
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B
2
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C
0
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D
1
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Solution

The correct option is B 2
We know that |f(x)|=f(x) for f(x)0 and |f(x)|=f(x) for f(x)<0

Here, |x+2|>0x[1,1]

Hence, |x+2|=x+2

Hence, integration becomes:-

111.dx

=[x]11

=2

Hence, answer is option-(B).

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