wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate:11[1+x+x21x+x2]dx

Open in App
Solution

Let I=11[1+x+x21x+x2]dx
And f(x)=[1+x+x21xx2]
Then f(x)=[1+(x)+(x)21(x)(x)2]==[1x+x21+xx2]=f(x)
I=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Vn Method
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon