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Question

Evaluate: 211(x+1)(x+3)dx

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Solution

1(x+3)(x+1)=12(x+1)12(x+3)=12(x+1)12(x+3)dx=12(x+1)dx12(x+3)dx=121x+1dx121x+3dx=12ln|x+1|12ln|x+3|
Computing the boundaries:
211(x+3)(x+1)dx=ln(3)ln(5)2(ln(2)2ln(2))=ln(3)ln(5)2(ln(2)2ln(2))=ln(310)2+ln(2)

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