Question

Evaluate :
${\int }_{-1}^{2}xdx$

Answer 1

$I={\int }_{-1}^{2}xdx$

Here not given where is it's fraction part, So I'm going to solve it simple.

$={\left[\frac{x^2}{2}\right]}_{-1}^2$

$=\frac{4}{2}-\frac{1}{2}$

$=\frac{3}{2}$