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Question

Evaluate: 1x+3x+2dx

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Solution

1x+3x+2dx

=x+3+x+2x+3x2dx=x+3dx+x+2dx

=(x+3)3/23/2+(x+2)3/23/2+c

=23[(x+2)3/2+(x+3)3/2]+c.

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