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Question

Evaluate:
2sinxsinx+cosxdx.

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Solution

Now,
2sinxsinx+cosxdx
=sinx+cosxsinx+cosxdxcosxsinxsinx+cosxdx
= dxd(sinx+cosx)sinx+cosxdx
=xlog|(sinx+cosx)|+c [ Where c is integrating constant]

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