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Question

Evaluate: 2x+1x2+xdx

A
logx+log(x+1)
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B
32logx
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C
12log(x+1)
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D
None of these
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Solution

The correct option is A logx+log(x+1)
Let 2x+1x2+x=2x+1x(x+1)=x+x+1x(x+1)=1x+11+x
2x+xx2+xdx
=1x+11+xdx
=logx+log(x+1)

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