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Question

Evaluate:
2x(x2+1)(x2+3)dx.

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Solution

2x(x2+1)(x2+3)dx
x2=m
2xdx=dm
dm(m+1)(m+3)
12[dm(m+1)dmm+3]
=12[In|m+1|In|m+3|]+c
=12[Inx2+1Inx2+3]+c

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