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Question

Evaluate :
(3sinx2)cosx5cos2x4sinxdx

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Solution

I=(3sinx2)cosx5cos2x4sinxdx

I=(3sinx2)cosx5(1sin2x)4sinxdx

Put sinx=t
cosx dx=dt

I=3t25(1t2)4tdt

I=3t24+t24tdt

I=3t2(t2)2dt

I=3(t2)+4(t2)2dt

I=3t2dt+4(t2)2dt

I=3log(t2)4t2+C

I=3log|sinx2|4sinx2+C

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