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Question

Evaluate (7x+2)7x2+4x+5dx
(where C is constant of integration)

A
12ln7x2+4x+5+C
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B
12ln7x2+4x+5+C
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C
12ln7x24x+5+C
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D
12ln7x24x+5+C.
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Solution

The correct option is A 12ln7x2+4x+5+C
Let I=(7x+2)7x2+4x+5dx
Put 7x2+4x+5=t2(7x+2)dx=dt
I=12dtt=12ln|t|+C
I=12ln7x2+4x+5+C.

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