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Question

Evaluate cosxcos(xa)dx
(where C is constant of integration)

A
xcosasinaln|sec(xa)|+C
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B
xcosa+sinaln|sec(xa)|+C
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C
xcosasinaln|sec(xa)|+C
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D
xcosa+sinaln|sec(xa)|+C
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Solution

The correct option is A xcosasinaln|sec(xa)|+C
Let I=cos(x)cos(xa)dx
I=cos(xa+a)cos(xa)dx
I=cos(xa)cosasin(xa)sinacos(xa)dx
I=(cosatan(xa)sina)dx
I=xcosasinaln|sec(xa)|+C

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