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Question

Evaluate: cosx+xsinxx(x+cosx)dx

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Solution

I=cosx+xsinxx(x+cosx)dx

I=(cosx+x)+(xsinxx)x(x+cosx)dx

I=1x(x+cosx)(x+cosx)+x(sinx1)x(x+cosx)dx

I=1xdx+(sinx1)x+cosxdx

Let x+cosx=u

du=(1sinx)dx

I=ln|x|+(1sinx)udu(1sinx)

I=ln|x|ln|u|+c

I=ln|x|ln|x+cosx|+c.

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