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Question

Evaluate dxx(1+x).

A
log(1+x)+c
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B
2log(x)+c
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C
6log(1+x2)+c
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D
2log(1+x)+c
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Solution

The correct option is D 2log(1+x)+c
Consider, I=dxx(1+x)

1+x=t dx2x=dt

I=2dtt

I=2ln(t)+c

I=2ln(1+x)+c.

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