wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate: sin2xsin4x+cos4xdx

Open in App
Solution

Given
sin2xsin4x+cos4x
=2sinxcosxsin4x+cos4xdx
Multiply numerator and denominator by sec4x
=2tanxcoxxsin4x+cos4xdx
Let u= tan x and du=sec2xdx
=2uu4+1du
=2uu4+1du
Let s=u2 and ds=2udu
=1s2+1ds
the internal of 1s2+1 is tan1s
=tan1s+C
=tan1u2+C
=tan1(tan2x)+C

1211437_1505704_ans_7972569d5b9f44669a3f42dd029622a8.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration by Partial Fractions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon