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Question

Evaluate: sin2xsin4x+cos4xdx

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Solution

Given
sin2xsin4x+cos4x
=2sinxcosxsin4x+cos4xdx
Multiply numerator and denominator by sec4x
=2tanxcoxxsin4x+cos4xdx
Let u= tan x and du=sec2xdx
=2uu4+1du
=2uu4+1du
Let s=u2 and ds=2udu
=1s2+1ds
the internal of 1s2+1 is tan1s
=tan1s+C
=tan1u2+C
=tan1(tan2x)+C

1211437_1505704_ans_7972569d5b9f44669a3f42dd029622a8.png

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